龙盟编程博客 | 无障碍搜索 | 云盘搜索神器
快速搜索
主页 > 软件开发 > JAVA开发 >

java基于swing实现的五子棋游戏代码(3)

时间:2014-11-14 11:06来源:网络整理 作者:网络 点击:
分享到:
public static void main(String[] args)throws NullPointerException{ new Main(); } public int value(int i,int j){ if(((state[i][j]==0)(state[i][j+1]==1)(state[i][j+2]==1)(state[i][j+3]==1)(state[i][j+4]

    public static void main(String[] args)throws NullPointerException{
            new Main();
    }
    public int value(int i,int j){

            if(((state[i][j]==0)&&(state[i][j+1]==1)&&(state[i][j+2]==1)&&(state[i][j+3]==1)&&(state[i][j+4]==1)&&(state[i][j+5]==0))||
                           ((state[i][j]==0)&&(state[i][j-1]==1)&&(state[i][j-2]==1)&&(state[i][j-3]==1)&&(state[i][j-4]==1)&&(state[i][j-5]==0))||
                           ((state[i][j]==0)&&(state[i-1][j]==1)&&(state[i-2][j]==1)&&(state[i-3][j]==1)&&(state[i-4][j]==1)&&(state[i-5][j]==0))||
                           ((state[i][j]==0)&&(state[i+1][j]==1)&&(state[i+2][j]==1)&&(state[i+3][j]==1)&&(state[i+4][j]==1)&&(state[i+5][j]==0))||
                           ((state[i][j]==0)&&(state[i+1][j+1]==1)&&(state[i+2][j+2]==1)&&(state[i+3][j+3]==1)&&(state[i+4][j+4]==1)&&(state[i+5][j+5]==0))||           //空红红红红空型
                           ((state[i][j]==0)&&(state[i-1][j+1]==1)&&(state[i-2][j+2]==1)&&(state[i-3][j+3]==1)&&(state[i-4][j+4]==1)&&(state[i-5][j+5]==0))||
                           ((state[i][j]==0)&&(state[i+1][j-1]==1)&&(state[i+2][j-2]==1)&&(state[i+3][j-3]==1)&&(state[i+4][j-4]==1)&&(state[i+5][j-5]==0))||
                           ((state[i][j]==0)&&(state[i-1][j-1]==1)&&(state[i-2][j-2]==1)&&(state[i-3][j-3]==1)&&(state[i-4][j-4]==1)&&(state[i-5][j-5]==0))){
                           value[i][j]=8;
                           return value[i][j];
                }
                else if(((state[i][j]==0)&&(state[i][j+1]==2)&&(state[i][j+2]==2)&&(state[i][j+3]==2)&&(state[i][j+4]==2)&&(state[i][j+5]==0))||
                                ((state[i][j]==0)&&(state[i][j-1]==2)&&(state[i][j-2]==2)&&(state[i][j-3]==2)&&(state[i][j-4]==2)&&(state[i][j-5]==0))||
                                ((state[i][j]==0)&&(state[i-1][j]==2)&&(state[i-2][j]==2)&&(state[i-3][j]==2)&&(state[i-4][j]==2)&&(state[i-5][j]==0))||                   //空红红红红空型
                                ((state[i][j]==0)&&(state[i+1][j]==2)&&(state[i+2][j]==2)&&(state[i+3][j]==2)&&(state[i+4][j]==2)&&(state[i+5][j]==0))||
                                ((state[i][j]==0)&&(state[i+1][j+1]==2)&&(state[i+2][j+2]==2)&&(state[i+3][j+3]==2)&&(state[i+4][j+4]==2)&&(state[i+5][j+5]==0))||
                                ((state[i][j]==0)&&(state[i-1][j+1]==2)&&(state[i-2][j+2]==2)&&(state[i-3][j+3]==2)&&(state[i-4][j+4]==2)&&(state[i-5][j+5]==0))||
                                ((state[i][j]==0)&&(state[i+1][j-1]==2)&&(state[i+2][j-2]==2)&&(state[i+3][j-3]==2)&&(state[i+4][j-4]==2)&&(state[i+5][j-5]==0))||
                                ((state[i][j]==0)&&(state[i-1][j-1]==2)&&(state[i-2][j-2]==2)&&(state[i-3][j-3]==2)&&(state[i-4][j-4]==2)&&(state[i-5][j-5]==0))){
                                value[i][j]=7;
                                return value[i][j];
                }
                else if(((state[i][j]==0)&&(state[i][j+1]==1)&&(state[i][j+2]==1)&&(state[i][j+3]==1)&&(state[i][j+4]==0))||
                                ((state[i][j]==0)&&(state[i][j-1]==1)&&(state[i][j-2]==1)&&(state[i][j-3]==1)&&(state[i][j-4]==0))||
                                ((state[i][j]==0)&&(state[i+1][j]==1)&&(state[i+2][j]==1)&&(state[i+3][j]==1)&&(state[i+4][j]==0))||
                                ((state[i][j]==0)&&(state[i-1][j]==1)&&(state[i-2][j]==1)&&(state[i-3][j]==1)&&(state[i-4][j]==0))||                            //空红红红空型
                                ((state[i][j]==0)&&(state[i+1][j+1]==1)&&(state[i+2][j+2]==1)&&(state[i+3][j+3]==1)&&(state[i+4][j+4]==0))||
                                ((state[i][j]==0)&&(state[i+1][j-1]==1)&&(state[i+2][j-2]==1)&&(state[i+3][j-3]==1)&&(state[i+4][j-4]==0))||
                                ((state[i][j]==0)&&(state[i-1][j+1]==1)&&(state[i-2][j+2]==1)&&(state[i-3][j+3]==1)&&(state[i-4][j+4]==0))||
                                ((state[i][j]==0)&&(state[i-1][j-1]==1)&&(state[i-2][j-2]==1)&&(state[i-3][j-3]==1)&&(state[i-4][j-4]==0))||

精彩图集

赞助商链接