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java基于swing实现的五子棋游戏代码(17)

时间:2014-11-14 11:06来源:网络整理 作者:网络 点击:
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((state[i][j-2]==2)(state[i][j-1]==2)(state[i][j]==0)(state[i][j+1]==2)(state[i][j+2]==1))|| ((state[i-2][j]==2)(state[i-1][j]==2)(state[i][j]==0)(state[i+1][j]==2)(state[i+2][j]==1))|| ((state[i+2][j

                                 ((state[i][j-2]==2)&&(state[i][j-1]==2)&&(state[i][j]==0)&&(state[i][j+1]==2)&&(state[i][j+2]==1))||
                                 ((state[i-2][j]==2)&&(state[i-1][j]==2)&&(state[i][j]==0)&&(state[i+1][j]==2)&&(state[i+2][j]==1))||
                                 ((state[i+2][j-2]==2)&&(state[i+1][j-1]==2)&&(state[i][j]==0)&&(state[i-1][j+1]==2)&&(state[i-2][j+2]==1))||
                                 ((state[i-2][j+2]==2)&&(state[i-1][j+1]==2)&&(state[i][j]==0)&&(state[i+1][j-1]==2)&&(state[i+2][j-2]==1))||
                                 ((state[i][j+2]==2)&&(state[i][j+1]==2)&&(state[i][j]==0)&&(state[i][j-1]==2)&&(state[i][j-2]==1))||
                                 ((state[i+2][j]==2)&&(state[i+1][j]==2)&&(state[i][j]==0)&&(state[i-1][j]==2)&&(state[i-2][j]==1))||
                                 ((state[i-2][j+2]==2)&&(state[i-1][j+1]==2)&&(state[i][j]==0)&&(state[i+1][j-1]==2)&&(state[i+2][j-2]==1))||
                                 ((state[i+2][j-2]==2)&&(state[i+1][j-1]==2)&&(state[i][j]==0)&&(state[i-1][j+1]==2)&&(state[i-2][j+2]==1))){
                                 value[i][j]=3;
                                 return value[i][j];
                }
                else if(((state[i][j]==0)&&(state[i][j+1]==1)&&(state[i][j+2]==0))||
                                ((state[i][j]==0)&&(state[i][j-1]==1)&&(state[i][j-2]==0))||
                                ((state[i][j]==0)&&(state[i+1][j]==1)&&(state[i+2][j]==0))||
                                ((state[i][j]==0)&&(state[i-1][j]==1)&&(state[i-2][j]==0))||                               //空红空
                                ((state[i][j]==0)&&(state[i+1][j+1]==1)&&(state[i+2][j+2]==0))||
                                ((state[i][j]==0)&&(state[i+1][j-1]==1)&&(state[i+2][j-2]==0))||
                                ((state[i][j]==0)&&(state[i-1][j+1]==1)&&(state[i-2][j+2]==0))||
                                ((state[i][j]==0)&&(state[i-1][j-1]==1)&&(state[i-2][j-2]==0))||

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