龙盟编程博客 | 无障碍搜索 | 云盘搜索神器
快速搜索
主页 > 软件开发 > JAVA开发 >

Java实现Linux下双守护进程(2)

时间:2014-10-29 02:17来源:网络整理 作者:网络 点击:
分享到:
复制代码 代码如下: public class GuardServer { private String servername; public GuardServer(String servername) { this.servername = servername; } public void startServer(String cmd) throws Exce

复制代码 代码如下:

 public class GuardServer {
     private String servername;
 
     public GuardServer(String servername) {
         this.servername = servername;
     }
 
     public void startServer(String cmd) throws Exception {
         System.out.println("Start Server : " + cmd);
         //将命令分开
 //        String[] cmds = cmd.split(" ");
 //        ProcessBuilder builder = new ProcessBuilder(cmds);
    
         //
         ProcessBuilder builder=new ProcessBuilder(new String[]{"/bin/sh","-c",cmd});
         //将服务器程序的输出定位到/dev/tty
         builder.redirectOutput(new File("/dev/tty"));
         builder.redirectError(new File("/dev/tty"));
         builder.start(); // throws IOException
         Thread.sleep(10000);
     }
 
     /**
      * 检测服务是否存在
      *
      * @return 返回配置的java程序的pid
      * @return pid >0 返回的是 pid <=0 代表指定java程序未运行
      * **/
     public int checkServer() throws Exception {
         int pid = -1;
         Process process = null;
         BufferedReader reader = null;
         process = Runtime.getRuntime().exec("jps -l");
         reader = new BufferedReader(new InputStreamReader(process.getInputStream()));
         String line;
         while ((line = reader.readLine()) != null) {
             String[] strings = line.split("\\s{1,}");
             if (strings.length < 2)
                 continue;
             if (strings[1].contains(servername)) {
                 pid = Integer.parseInt(strings[0]);
                 break;
             }
         }
         reader.close();
         process.destroy();
         return pid;
     }
 }

3、GuardAMain实现

精彩图集

赞助商链接