Oracle SQL:经典查询练手第三篇(1)(2)
各试题解答如下(欢迎大家指出不同的方法或建议!): /* --------1、改变NLS_LANG的值,让SELECTTO_CHAR(SALARY,'L99,999.99')FROMHR.EMPLOYEESWHEREROWNUM5输出结果的货币单
各试题解答如下(欢迎大家指出不同的方法或建议!):
- /*--------1、改变NLS_LANG 的值,让SELECT TO_CHAR(SALARY,'L99,999.99') FROM HR.EMPLOYEES WHERE ROWNUM < 5 输出结果的货币单位是¥和$。---------*/
- -----在没有设置NLS_LANG的情况下:
- SQL> SELECT TO_CHAR(SALARY,'L99,999.99')
- 2 FROM HR.EMPLOYEES
- 3 WHERE ROWNUM < 5;
- TO_CHAR(SALARY,'L99,999.99')
- ----------------------------
- ¥24,000.00
- ¥20,000.00
- ¥20,000.00
- ¥9,000.00
- SQL> SELECT TO_CHAR(SALARY,'$99,999.99')
- 2 FROM HR.EMPLOYEES
- 3 WHERE ROWNUM < 5;
- TO_CHAR(SALARY,'$99,999.99')
- ----------------------------
- $24,000.00
- $20,000.00
- $20,000.00
- $9,000.00
- /*--说明:对于'$99,999.99'格式符:
- L:表示强制显示当地货币符号
- $: 表示显示美元符号
- 9: 表示一个数字
- 0: 表示强制0显示
- .: 表示一个小数点
- ,: 表示一个千位分隔符
- --------------*/
- /*--------2、列出前五位每个员工的名字,工资、涨薪后的的工资(涨幅为8%),以“元”为单位进行四舍五入。---------*/
- SQL> SELECT FIRST_NAME,SALARY,ROUND(SALARY * 1.08) FROM HR.EMPLOYEES
- 2 WHERE ROWNUM <=5;
- FIRST_NAME SALARY ROUND(SALARY*1.08)
- -------------------- ---------- ------------------
- Steven 24000.00 25920
- Neena 20000.00 21600
- Lex 20000.00 21600
- Alexander 9000.00 9720
- Bruce 6000.00 6480
- /*--------3、找出谁是最高领导,将名字按大写形式显示。---------*/
- SQL> SELECT UPPER(FIRST_NAME || ' ' || LAST_NAME) AS NAME
- 2 FROM HR.EMPLOYEES
- 3 WHERE MANAGER_ID IS NULL;
- NAME
- ----------------------------------------------
- STEVEN KING
- /*--------4、找出David 的直接领导的名字。---------*/
- SQL> SELECT UPPER(FIRST_NAME ||' ' || LAST_NAME) AS NAME
- 2 FROM HR.EMPLOYEES
- 3 WHERE EMPLOYEE_ID IN(
- 4 SELECT MANAGER_ID FROM HR.EMPLOYEES
- 5 WHERE FIRST_NAME = 'David' AND LAST_NAME = 'Austin');
- NAME
- ----------------------------------------------
- ALEXANDER HUNOLD
- --或采用以下方法
- SQL> SELECT UPPER( EMP1.FIRST_NAME ||' ' || EMP1.LAST_NAME) AS NAME
- 2 FROM HR.EMPLOYEES EMP1,HR.EMPLOYEES EMP2
- 3 WHERE EMP1.EMPLOYEE_ID = EMP2.MANAGER_ID
- 4 AND EMP2.FIRST_NAME = 'David' AND EMP2.LAST_NAME = 'Austin';
- NAME
- ----------------------------------------------
- ALEXANDER HUNOLD
- /*--------5、First_Name 为Alexander,LAST_NAME为Hunold领导谁。(谁向David 报告)。---------*/
- SQL> SELECT UPPER(FIRST_NAME ||' ' || LAST_NAME) AS NAME
- 2 FROM HR.EMPLOYEES
- 3 WHERE MANAGER_ID IN(
- 4 SELECT EMPLOYEE_ID FROM HR.EMPLOYEES
- 5 WHERE FIRST_NAME = 'Alexander' AND LAST_NAME = 'Hunold');
- NAME
- ----------------------------------------------
- BRUCE ERNST
- DAVID AUSTIN
- VALLI PATABALLA
- DIANA LORENTZ
- --或采用以下方法
- SQL> SELECT UPPER( EMP1.FIRST_NAME || ' ' || EMP1.LAST_NAME) AS NAME
- 2 FROM HR.EMPLOYEES EMP1,HR.EMPLOYEES EMP2
- 3 WHERE EMP1.MANAGER_ID = EMP2.EMPLOYEE_ID
- 4 AND EMP2.FIRST_NAME = 'Alexander' AND EMP2.LAST_NAME = 'Hunold';
- NAME
- ----------------------------------------------
- BRUCE ERNST
- DAVID AUSTIN
- VALLI PATABALLA
- DIANA LORENTZ
- /*--------6、哪些员工的工资高于他直接上司的工资,列出员工的名字和工资,上司的名字和工资。---------*/
- SQL> SELECT E.FIRST_NAME,E.SALARY,M.FIRST_NAME,M.SALARY
- 2 FROM EMPLOYEES E,EMPLOYEES M
- 3 WHERE E.MANAGER_ID = M.EMPLOYEE_ID AND E.SALARY > M.SALARY;
- FIRST_NAME SALARY FIRST_NAME SALARY
- -------------------- ---------- -------------------- ----------
- Lisa 11500.00 Gerald 11000.00
- Ellen 11000.00 Eleni 10500.00
- --要是只列出员工的名字与工资的话,还可以这样:
- SQL> SELECT E.FIRST_NAME,E.SALARY
- 2 FROM EMPLOYEES E WHERE E.SALARY >
- 3 (SELECT M.SALARY FROM EMPLOYEES M
- 4 WHERE E.MANAGER_ID = M.EMPLOYEE_ID);
- FIRST_NAME SALARY
- -------------------- ----------
- Lisa 11500.00
- Ellen 11000.00
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