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14.7.4 Addition operator

时间:2009-12-23 15:42来源:未知 作者:admin 点击:
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For an operation of the form x + y, binary operator overload resolution (?4. 2.4) is applied to select a specific operator implementation. The operands are converted to the parameter types of the selected operator, and the type of the resul

  For an operation of the form x + y, binary operator overload resolution (?4.
  2.4) is applied to select a
  specific operator implementation. The operands are converted to the
  parameter types of the selected
  operator, and the type of the result is the return type of the operator.
  The predefined addition operators are listed below. For numeric and
  enumeration types, the predefined
  addition operators compute the sum of the two operands. When one or both
  operands are of type string,
  the predefined addition operators concatenate the string representation of
  the operands.
  ?Integer addition:
  int operator +(int x, int y);
  uint operator +(uint x, uint y);
  long operator +(long x, long y);
  ulong operator +(ulong x, ulong y);
  In a checked context, if the sum is outside the range of the result type, a
  System.OverflowException is thrown. In an unchecked context, overflows are
  not reported and
  any significant high-order bits outside the range of the result type are
  discarded.
  ?Floating-point addition:
  float operator +(float x, float y);
  double operator +(double x, double y);
  The sum is computed according to the rules of IEC 60559 arithmetic. The
  following table lists the
  results of all possible combinations of nonzero finite values, zeros,
  infinities, and NaN?s. In the table, x
  and y are nonzero finite values, and z is the result of x + y. If x and y
  have the same magnitude but
  opposite signs, z is positive zero. If x + y is too large to represent in
  the destination type, z is an
  infinity with the same sign as x + y. If x + y is too small to represent in
  the destination type, z is a
  zero with the same sign as x + y.
  
      y   +0  -0  +8  -8  NaN
  x   z   x   x   +8  -8  NaN
  +0  y   +0  +0  +8  -8  NaN
  -0  y   +0  -0  +8  -8  NaN
  +8  +8  +8  +8  +8  NaN NaN
  -8  -8  -8  -8  NaN -8  NaN
  NaN NaN NaN NaN NaN NaN NaN
  
  ?Decimal addition:
  decimal operator +(decimal x, decimal y);
  If the resulting value is too large to represent in the decimal format, a
  System.OverflowException
  is thrown. The scale of the result, before any rounding, is the larger of
  the scales of the two operands.
  Decimal addition is equivalent to using the addition operator of type
  System.Decimal.
  ?Enumeration addition. Every enumeration type implicitly provides the
  following predefined operators,
  where E is the enum type, and U is the underlying type of E:
  E operator +(E x, U y);
  E operator +(U x, E y);
  The operators are evaluated exactly as (E)((U)x + (U)y).
  ?String concatenation:
  string operator +(string x, string y);
  string operator +(string x, object y);
  string operator +(object x, string y);
  The binary + operator performs string concatenation when one or both
  operands are of type string. If
  an operand of string concatenation is null, an empty string is substituted.
  Otherwise, any non-string
  argument is converted to its string representation by invoking the virtual
  ToString method inherited
  from type object. If ToString returns null, an empty string is substituted.
  [Example:
  using System;
  class Test
  {
  static void Main() {
  string s = null;
  Console.WriteLine("s = >" + s + "<"); // displays s = ><
  int i = 1;
  Console.WriteLine("i = " + i); // displays i = 1
  float f = 1.2300E+15F;
  Console.WriteLine("f = " + f); // displays f = 1.23E+15
  decimal d = 2.900m;
  Console.WriteLine("d = " + d); // displays d = 2.900
  }
  }
  end example]
  The result of the string concatenation operator is a string that consists
  of the characters of the left
  operand followed by the characters of the right operand. The string
  concatenation operator never returns
  a null value. A System.OutOfMemoryException may be thrown if there is not
  enough memory
  available to allocate the resulting string.
  ?Delegate combination. Every delegate type implicitly provides the
  following predefined operator, where
  D is the delegate type:
  D operator +(D x, D y);
  The binary + operator performs delegate combination when both operands are
  of some delegate type D.
  (If the operands have different delegate types, a compile-time error
  occurs.) If the first operand is null,
  Chapter 14 EXPressions
  161
  the result of the operation is the value of the second operand (even if
  that is also null). Otherwise, if the
  second operand is null, then the result of the operation is the value of
  the first operand. Otherwise, the
  result of the operation is a new delegate instance that, when invoked,
  invokes the first operand and then
  invokes the second operand. [Note: For examples of delegate combination,
  see ?4.7.5 and ?2.3. Since
  System.Delegate is not a delegate type, operator + is not defined for it.
  end note]
  
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