ORACLE 10g新增了阶层查询操作符PRIOR，CONNECT_BY_ROOT。
PRIOR
阶层查询的CONNECY BY condition的条件式需要用到PRIOR来指定父节点，作为运算符，PRIOR和加(+)减(-)运算的优先级相同。
阶层查询
语法：START WITH condition CONNECT BY NOCYCLE condition
◆START WITH 指定阶层的根
◆CONNECT BY 指定阶层的父/子关系
◆NOCYCLE 存在CONNECT BY LOOP的纪录时，也返回查询结果。
◆condition ... PRIOR expr = expr 或者 ... expr = PRIOR expr
例：
CONNECT BY last_name != 'King' AND PRIOR employee_id = manager_id ...
CONNECT BY PRIOR employee_id = manager_id and
PRIOR account_mgr_id = customer_id ... |
CONNECT_BY_ROOT
查询指定根的阶层数据。
CONNECT BY子句的例子
通过CONNECT BY子句定义职员和上司的关系。
SQL>SELECT employee_id, last_name, manager_id
FROM employees
CONNECT BY PRIOR employee_id = manager_id;
EMPLOYEE_ID LAST_NAME MANAGER_ID
----------- ------------------------- ----------
101 Kochhar 100
108 Greenberg 101
109 Faviet 108
110 Chen 108
111 Sciarra 108
112 Urman 108
113 Popp 108
200 Whalen 101 |
LEVEL的例子
通过LEVEL虚拟列表示节点的关系。
SQL>SELECT employee_id, last_name, manager_id, LEVEL
FROM employees
CONNECT BY PRIOR employee_id = manager_id;
EMPLOYEE_ID LAST_NAME MANAGER_ID LEVEL
----------- ------------------------- ---------- ----------
101 Kochhar 100 1
108 Greenberg 101 2
109 Faviet 108 3
110 Chen 108 3
111 Sciarra 108 3
112 Urman 108 3
113 Popp 108 3
|
START WITH子句的例子
通过START WITH指定根节点，ORDER SIBLINGS BY保持阶层的顺序。
SQL>SELECT last_name, employee_id, manager_id, LEVEL
FROM employees
START WITH employee_id = 100
CONNECT BY PRIOR employee_id = manager_id
ORDER SIBLINGS BY last_name;
LAST_NAME EMPLOYEE_ID MANAGER_ID LEVEL
------------------------- ----------- ---------- ----------
King 100 1
Cambrault 148 100 2
Bates 172 148 3
Bloom 169 148 3
Fox 170 148 3
Kumar 173 148 3
Ozer 168 148 3
Smith 171 148 3
De Haan 102 100 2
Hunold 103 102 3
Austin 105 103 4
Ernst 104 103 4
Lorentz 107 103 4
Pataballa 106 103 4
Errazuriz 147 100 2
Ande 166 147 3
Banda 167 147 3 |
