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Convert from type X to type Y

时间:2009-12-23 15:42来源:未知 作者:admin 点击:
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integer to String : int i = 42; String str = Integer.toString(i); or String str = "" + i double to String : String str = Double.toString(i); long to String : String str = Long.toString(l); float to String : String str = Float.toString(f); S

integer to String :

    int i = 42;    String str = Integer.toString(i);
  

  or
  
    String str = "" + i
  

  

double to String :

    String str = Double.toString(i);
  

  

long to String :

    String str = Long.toString(l);
  

  

float to String :

    String str = Float.toString(f);
  

  

String to integer :

    str = "25";    int i = Integer.valueOf(str).intValue();
  

  or
  
    int i = Integer.parseInt(str);
  

  

String to double :

    double d = Double.valueOf(str).doubleValue();
  

  

String to long :

    long l = Long.valueOf(str).longValue();
  

  or
  
    long l = Long.parseLong(str);
  

  

String to float :

    float f = Float.valueOf(str).floatValue();
  

  
  

decimal to binary :

    int i = 42;    String binstr = Integer.toBinaryString(i);
  

  
  

decimal to hexadecimal :

    int i = 42;    String hexstr = Integer.toString(i, 16);
  

  or
  
    String hexstr = Integer.toHexString(i);
  

  
  

hexadecimal (String) to integer :

    int i = Integer.valueOf("B8DA3", 16).intValue();
  

  or
  
    int i = Integer.parseInt("B8DA3", 16);     
  

  

  

ASCII code to String :

    int i = 64;    String aChar = new Character((char)i).toString();
  

  
  

integer to ASCII code (byte) :

    char c = 'A';    int i = (int) c; // i will have the value 65 decimal
  

  
  

To extract Ascii codes from a String :

      String test = "ABCD";   
   for ( int i = 0; i < test.length(); ++i ) {
   char c = test.charAt( i );
   int i = (int) c;
   System.out.println(i);
   }
  

  
  

integer to boolean :

    b = (i != 0);
  

  

boolean to integer :

    i = (b)?1:0;
  

  note :To catch illegal number conversion, try using the try/catch mechanism.
  

 try{
   i = Integer.parseInt(aString);
  } catch(NumberFormatException e) { }
  
  
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